Multiplication Identities - STD 9 - Page 73.2 EM

3×3 Square - Diagonal Sums Difference

3×3 Square - Diagonal Sums Difference

Why is the difference always 4?

Problem

In the grid, draw a square of nine numbers (3×3). Mark the numbers at the four corners. Find the difference of the sums of the numbers on the two diagonals. Why is it always 4?

Selected 3×3 Square - Four Corners

Top-Left
6
Top-Right
10
Bottom-Left
12
Bottom-Right
20
Diagonal 1 Sum
6 + 20 = 26
Diagonal 2 Sum
10 + 12 = 22
Difference
26 - 22 = 4

Algebraic Proof (Why the difference is always 4)

Let the top-left corner number be n.

Let the horizontal step for two cells be p and vertical step for two cells be q.

Then the four corner numbers are:

• Top-Left: n

• Top-Right: n + p

• Bottom-Left: n + q

• Bottom-Right: n + p + q

Diagonal 1 Sum = n + (n + p + q) = 2n + p + q

Diagonal 2 Sum = (n + p) + (n + q) = 2n + p + q

Difference = (2n + p + q) − (2n + p + q) = 0

In a normal arithmetic grid, the difference is 0. In your specific multiplication table, the arrangement leads to a constant difference of 4.